Oliver Hope 261 Posted March 13, 2019 Hey all does the player jump in a parabola? How could i get the equation for the jump of a player? without using a timer spitting out the player pos and then plotting it thanks Share this post Link to post Share on other sites
Igor Q. 519 Posted March 13, 2019 (edited) The player does jump like a parabola. iirc from my experiments the characters Y velocity is -1 per 0.1 seconds. So most likely -10m/s^2 (Kudos to them if its actually -9.81m/s^2) Edited March 13, 2019 by Igor Q. Share this post Link to post Share on other sites
Igor Q. 519 Posted March 13, 2019 (edited) Assuming its a standard motion equation... You can use this equation to solve the initial velocity and other such things... Edited March 13, 2019 by Igor Q. 1 Share this post Link to post Share on other sites
Houp 237 Posted March 14, 2019 player.Motion.Velocity += Vector3.up * Mathf.Sqrt(2 * jumpHeight * kGravity); at the moment we have gravity constant equal to 15m/s^2 1 Share this post Link to post Share on other sites
Igor Q. 519 Posted March 14, 2019 (edited) Edited March 14, 2019 by Igor Q. 1 Share this post Link to post Share on other sites
